Dictionary Algorithms

Dictionary Algorithms#

Note

Source: Contributed by PhD students in COMP 501 at Loyola University Chicago.

Dictionaries are one of Python’s most powerful data structures because they map keys to values with extremely fast lookup times. As programs grow in size and complexity, certain dictionary patterns appear again and again. This chapter covers the most important ones.

Counting with Dictionaries#

Counting occurrences is one of the most common uses of a dictionary.

words = ["apple", "banana", "apple", "pear", "banana", "apple"]
counts = {}

for w in words:
    if w not in counts:
        counts[w] = 1
    else:
        counts[w] += 1

print(counts)

Output:

{'apple': 3, 'banana': 2, 'pear': 1}

The .get() method makes this more concise:

counts = {}
for w in words:
    counts[w] = counts.get(w, 0) + 1

get(key, 0) returns the current count if the key exists, or 0 if it does not, avoiding a KeyError.

Run the counting pattern below, then change words — try counting the characters in a string such as "mississippi" instead:

>>> words = ["apple", "banana", "apple", "pear", "banana", "apple"]
>>> counts = {}
>>> for w in words:
...     counts[w] = counts.get(w, 0) + 1
...
>>> print(counts)
{'apple': 3, 'banana': 2, 'pear': 1}

Filtering Dictionaries#

Build a new dictionary containing only the key/value pairs that satisfy a condition:

scores = {"Alice": 95, "Bob": 82, "Carol": 71, "Diana": 99}
high_scores = {}

for name, score in scores.items():
    if score > 80:
        high_scores[name] = score

print(high_scores)

Output:

{'Alice': 95, 'Bob': 82, 'Diana': 99}

Grouping with Dictionaries#

Grouping places items that share a characteristic into lists under a common key.

words = ["apple", "ant", "banana", "berry", "car", "cat"]
groups = {}

for w in words:
    first = w[0]
    if first not in groups:
        groups[first] = []
    groups[first].append(w)

print(groups)

Output:

{'a': ['apple', 'ant'], 'b': ['banana', 'berry'], 'c': ['car', 'cat']}

The general grouping pattern is:

for item in data:
    key = some_property(item)
    if key not in groups:
        groups[key] = []
    groups[key].append(item)

setdefault is a convenient shorthand:

groups = {}
for w in words:
    groups.setdefault(w[0], []).append(w)

Reversing a Dictionary#

Swap keys and values. This works correctly only when values are unique and hashable. Run it and try adding a duplicate value to see what happens:

>>> grades = {"A": 90, "B": 80, "C": 70}
>>> reversed_grades = {v: k for k, v in grades.items()}
>>> print(reversed_grades)
{90: 'A', 80: 'B', 70: 'C'}

If values are not unique, later entries overwrite earlier ones during the reversal.

Merging Dictionaries#

Python 3.9+ provides the merge operator |. Run it and edit the dictionaries:

>>> a = {"x": 1, "y": 2}
>>> b = {"y": 3, "z": 4}
>>> c = a | b
>>> print(c)
{'x': 1, 'y': 3, 'z': 4}

If both dictionaries share a key, the right-hand dictionary wins. For older Python:

c = dict(a)
c.update(b)

Safe Access with .get()#

Use .get() to avoid KeyError when a key may not exist. Run it, then try adding "mode" to config and see how the result changes:

>>> config = {"debug": True}
>>> mode = config.get("mode", "production")
>>> print(mode)
production

Nested Dictionaries#

Dictionaries can hold other dictionaries, allowing hierarchical data. Run it and try reaching the science score:

>>> student = {
...     "name": "Alice",
...     "scores": {"math": 90, "science": 85}
... }
>>> print(student["scores"]["math"])
90

Algorithms on Lists of Dictionaries#

A list of dictionaries is a common format for tabular data (CSV rows, JSON records, API responses). Several dictionary algorithms apply naturally to this structure.

Frequency count over a field:

people = [
    {"name": "Alice", "age": 30},
    {"name": "Bob", "age": 25},
    {"name": "Cara", "age": 30},
]

freq = {}
for p in people:
    age = p["age"]
    freq[age] = freq.get(age, 0) + 1

print(freq)

Output:

{30: 2, 25: 1}

Index by a unique field (convert list → dictionary for O(1) lookup). Run it and look up a different person:

>>> people = [
...     {"name": "Alice", "age": 30},
...     {"name": "Bob", "age": 25},
...     {"name": "Cara", "age": 30},
... ]
>>> index = {p["name"]: p for p in people}
>>> print(index["Alice"])
{'name': 'Alice', 'age': 30}

Group records by a field:

by_age = {}
for p in people:
    by_age.setdefault(p["age"], []).append(p)

Group by Length (Practice)#

Implement a function that groups words by their length:

def group_by_length(words):
    groups = {}
    for w in words:
        groups.setdefault(len(w), []).append(w)
    return groups


print(group_by_length(["tea", "to", "apple", "jam", "bag"]))

Output:

{3: ['tea', 'jam', 'bag'], 2: ['to'], 5: ['apple']}

Real-World Applications#

Dictionary algorithms appear throughout software:

  • Analytics pipelines — counting events, computing statistics.

  • Search indexes — mapping words to the documents that contain them.

  • Grouping and categorization — organizing records by department, date, or status.

  • Summarizing survey data — counting responses per answer option.

Recognizing when a problem maps to one of these patterns is a key skill in Python programming.

Exercises#

  1. Count the frequency of each character in the string "mississippi".

  2. Given a list of words, filter out any word with fewer than four letters and return a dictionary mapping the remaining words to their lengths.

  3. Given a list of student records (each a dictionary with name, grade, and score), group them by grade.

  4. Reverse the dictionary {"red": 1, "green": 2, "blue": 3}. What happens if two keys share the same value?

  5. Merge two configuration dictionaries so that values in the second dictionary take priority over the first.

  6. Write a function top_n(counts, n) that returns the n most frequent items from a frequency dictionary as a sorted list of (item, count) tuples.